# Section 3.3 – Complex Roots of the Characteristic Equation

Directions. The following are review problems for the section. It is recommended you work the problems yourself, and then click "Answer" to check your answer. If you do not understand a problem, you can click "Video" to learn how to solve it.
1. Find the solution to the given initial value problem. $y''-2y'+5y=0\qquad y(\pi/2)=0,\quad y'(\pi/2)=2.$

$$y=-e^t(e^{-\frac{\pi}{2}})\sin(2t)$$

To see the full video page and find related videos, click the following link.