\(x=\dfrac{1\pm \sqrt{2} i}{2}\)
\(3\left(x+\dfrac{1}{3}\right)^2=\dfrac{10}{3}\quad \) so \(\quad x=-\dfrac{1}{3}\pm\dfrac{\sqrt{10}}{3}\)
\(x=-1, 1, 3\)
\(x=\dfrac{11}{6}\)
\(x=-4\pm\sqrt{6}\)