Answer: \(x\leq-\dfrac{3}{2}\quad \text{ OR } \quad x\geq4\)
Solution:
\(\begin{alignat}
4x-5 &\geq 11 \qquad &&\textrm{OR} \qquad 4x-5 &&\leq -11\\
4x &\geq 16 \qquad &&\textrm{OR} \qquad \qquad 4x &&\leq -6\\
x&\geq 4 \qquad &&\textrm{OR} \qquad \qquad x &&\leq-\dfrac{3}{2}
\end{alignat}\)
